STPS20L60C-Y Automotive power Schottky rectifier Datasheet production data Features A1 K Low forward voltage drop A2 Negligible switching losses Low thermal resistance K Avalanche capability specified AEC-Q101 qualified A2 A1 Description 2 D PAK This dual center tap Schottky rectifier is suited for STPS20L60CGY-TR switched mode power supplies and high frequency DC to DC converters. Table 1. Device summary 2 Packaged in D PAK, this device is intended for I 2 x 10 A use in high frequency inverters for automotive F(AV) applications. V 60 V RRM T 150 C j (max) V 0.56 V F (max) October 2012 Doc ID 022399 Rev 1 1/7 This is information on a product in full production. www.st.com 7Characteristics STPS20L60C-Y 1 Characteristics Table 2. Absolute ratings (limiting values, per diode) Symbol Parameter ValueUnit V Repetitive peak reverse voltage 60 V RRM I Forward rms current 30 A F(RMS) T = 140 C Per diode 10 C I Average forward current A F(AV) = 0.5 Per device 20 I Surge non repetitive forward current t = 10 ms, sinusoidal 220 A FSM p t = 2 s square, F = 1 kHz I Repetitive peak reverse current 1A p RRM P Repetitive peak avalanche power t = 1 s, T = 25 C 5800 W p j ARM T Storage temperature range -65 to + 175 C stg (1) T Operating junction temperature range -40 to + 150 C j dV/dt Critical rate of rise reverse voltage 10000 V/s dPtot 1 1. < condition to avoid thermal runaway for a diode on its own heatsink Rth(j-a) dTj Table 3. Thermal resistances Symbol Parameter ValueUnit Per diode 1.6 R Junction to case C/W th (j-c) Total 0.85 R Coupling 0.1 C/W th (c) When the diodes 1 and 2 are used simultaneously: T = P x R (per diode) + P x R j(diode 1) (diode1) th(j-c) (diode2) th(c) Table 4. Static electrical characteristics (per diode) Symbol Parameter Tests conditions Min.Typ.Max.Unit T = 25 C 350 A j (1) I Reverse leakage current V = V R R RRM T = 125 C 65 95 mA j T = 25 C I = 10 A 0.6 j F T = 125 C I = 10 A 0.48 0.56 j F (1) V Forward voltage drop V F T = 25 C I = 20 A 0.74 j F T = 125 C I = 20 A 0.62 0.7 j F 1. Pulse test: t = 380 s, < 2% p To evaluate the conduction losses use the following equation: 2 P = 0.42 x I + 0.014 x I F(AV) F (RMS) 2/7 Doc ID 022399 Rev 1